Как создать файл json php

Подскажите, как создать файл JSON и закинуть туда одну текстовую строчку

Доброго времени суток!)) Пытаюсь открыть для себя JSON, но пока смутно что-то понимаю.

Скажите, как вообще файл JSON создать. Читал, что можно обычный Блокнот сохранить в формате JSON и вперед. Но как внутреннюю структуру организовать?

И вопрос еще. Например, в PHP создаю я простую переменную и присваиваю ей простейший текст)) Hello, World!))

Как ее в файл JSON записать?

Заранее благодарен за ответ))

есть база даных и как туда закинуть файл .sql
у меня есть база даных и как туда закинуть файл .sql

Подскажите пожалуйста как в выпадающем списке сделать одну строчку жирной?
Здравствуйте, подскажите пожалуйста как в выпадающем списке сделать предпоследнюю строчку жирной? .

У меня есть список в классе. Как я могу закинуть туда элемент из другого метода?
У меня есть список в классе. Как я могу закинуть туда элемент из другого метода?

Как создать файл и записать туда информацию
как создать файл Jurnal.txt using System; using System.IO; using System.Collections.Generic;.

Сообщение от ВеликийГуру
Сообщение от ВеликийГуру
Сообщение от Jewbacabra

И тогда в json-файл будет записан Hello, world?

Или же внутри json-файла необходимо написать структуру по типу

Просто я имею довольно мутные представления в этом вопросе.

Заранее благодарен за ответ))

Сообщение от ВеликийГуру

Сообщение от Jewbacabra

Как создать файл и записать туда строку?
if (!File.Exists(&quot;WI-FI.cmd&quot;)) < File.Create(&quot;WI-FI.cmd&quot;); .

Как программно создать архив, и засунуть туда файл
Всем привет. ))) Подскажите пожалуйста как программно создать архив, и засунуть туда файл. За.

Как на С# создать вордовский файл, а затем сохранить туда табличный отчет
Добрый вечер, уважаемые форумчане))) Есть БД, мы ее заполняем, затем выбираем из нее необходимые.

Как добавить, удалить, обновить, прочитать только одну запись в JSON файл?
Вопросы 1. Как добавить, удалить, обновить, прочитать только одну запись в JSON файл? 2. Можно ли.

Из asp СОЗДАТЬ .doc файл, занести туда какие-либо данные и отослать созданный файл клиенту
Привет. Реально ли сделать такую фишку. Из asp СОЗДАТЬ .doc файл, занести туда какие-либо.

How to Create and Parse JSON Data with PHP

In this snippet, you can find a step-by-step guide on how to create and parse JSON data with PHP. Follow the steps and you’ll manage to meet your goal easily.

The data structures of JSON are identical to PHP arrays. There exist specific built-in functions that allow encoding and decoding JSON data. They are json_encode() and json_decode() functions. But, take into account that these functions only operate with string data, operated only with UTF-8.

In PHP, the first function is applied for encoding a value into the format of JSON. In the example below, you can see the process of encoding an associative PHP array into an object of JSON:

Its output will look as follows:

In the same way, an indexed PHP array may be encoded into an array of JSON:

And, the output is the following:

An important note: while an associative array may get encoded as an object, a non-associative one- both as an object and an array.

For parsing a JSON data you can use decoding. It is as simple as encoding. It is mainly applied for converting a JSON encoded string into a matching data type of PHP.

For a better understanding, check out the example below:

Here is the output of the example above:

So, by default, an object is returned by the json_decode() function. However, an optional parameter such as $assoc can be indicated. Here is how it can look like:

Its output will be the following:

In the next example, it is illustrated how to decode the data of JSON, accessing individual elements of an array or an object:

Also, the decoded data may be looped through using the foreach() loop in this way:

Describing JSON

JSON or the JavaScript Object Notation is a data-interchange format allowing to parse and create straightforwardly. It is a text-based format, simple in writing and understanding for computers and humans.

JSON stands on two primary structures: object and array. The first one is known as a collection of value/key pairs. The second one is an ordered value-list. Keys are always considered strings in the JSON format, while the values can be something like an object, array, string, number, and so on.

Как создать файл json php

In this article, we are going to generate a JSON file in PHP by using an array. JSON stands for JavaScript object notation, which is used for storing and exchanging data. JSON is text, written with JavaScript object notation.

Structure:

Example:

Properties:

1. JSON doesn’t use an end tag
2. It is shorter.
3. It is quicker to read and write.
4. It can use arrays.

Approach: In this article, we can generate JSON data using an array., create an array

Syntax:

Example:

Use json_encode() to convert array to JSON. It is used to convert array to JSON

Syntax:

Example: Place the file in the path using file_put_contents()

The file_name is the JSON to be saved and json_object is the object after JSON from the array is created.

Как создать файл json php

(opens new window) ) is a platform and language independent way of serializing objects into plaintext. Because it is often used on web and so is PHP, there is a basic extension

(opens new window) for working with JSON in PHP.

# Decoding a JSON string

(opens new window) function takes a JSON-encoded string as its first parameter and parses it into a PHP variable.

Normally, json_decode() will return an object of \stdClass

(opens new window) if the top level item in the JSON object is a dictionary or an indexed array if the JSON object is an array. It will also return scalar values or NULL for certain scalar values, such as simple strings, "true" , "false" , and "null" . It also returns NULL on any error.

(opens new window) to view the types and values of each property on the object we decoded above.

Output (note the variable types):

Note: The variable types in JSON were converted to their PHP equivalent.

(opens new window) for JSON objects instead of returning an object, pass true as the second parameter

Output (note the array associative structure):

The second parameter ( $assoc ) has no effect if the variable to be returned is not an object.

Note: If you use the $assoc parameter, you will lose the distinction between an empty array and an empty object. This means that running json_encode() on your decoded output again, will result in a different JSON structure.

If the JSON string has a "depth" more than 512 elements (20 elements in versions older than 5.2.3, or 128 in version 5.2.3) in recursion, the function json_decode() returns NULL . In versions 5.3 or later, this limit can be controlled using the third parameter ( $depth ), as discussed below.

According to the manual:

PHP implements a superset of JSON as specified in the original [» RFC 4627](http://www.faqs.org/rfcs/rfc4627) — it will also encode and decode scalar types and NULL. RFC 4627 only supports these values when they are nested inside an array or an object. Although this superset is consistent with the expanded definition of "JSON text" in the newer [» RFC 7159](http://www.faqs.org/rfcs/rfc7159) (which aims to supersede RFC 4627) and [» ECMA-404](http://www.ecma-international.org/publications/files/ECMA-ST/ECMA-404.pdf), this may cause interoperability issues with older JSON parsers that adhere strictly to RFC 4627 when encoding a single scalar value.

This means, that, for example, a simple string will be considered to be a valid JSON object in PHP:

But simple strings, not in an array or object, are not part of the RFC 4627

(opens new window) standard. As a result, such online checkers as JSLint

(opens new window) (in RFC 4627 mode) will give you an error.

There is a third $depth parameter for the depth of recursion (the default value is 512 ), which means the amount of nested objects inside the original object to be decoded.

There is a fourth $options parameter. It currently accepts only one value, JSON_BIGINT_AS_STRING . The default behavior (which leaves off this option) is to cast large integers to floats instead of strings.

Invalid non-lowercased variants of the true, false and null literals are no longer accepted as valid input.

So this example:

Similar behavior occurs for false and null .

Note that json_decode() will return NULL if the string cannot be converted.

It is not safe to rely only on the return value being NULL to detect errors. For example, if the JSON string contains nothing but "null" , json_decode() will return null , even though no error occurred.

# Encoding a JSON string

(opens new window) function will convert a PHP array (or, since PHP 5.4, an object which implements the JsonSerializable interface) to a JSON-encoded string. It returns a JSON-encoded string on success or FALSE on failure.

During encoding, the PHP data types string, integer, and boolean are converted to their JSON equivalent. Associative arrays are encoded as JSON objects, and – when called with default arguments – indexed arrays are encoded as JSON arrays. (Unless the array keys are not a continuous numeric sequence starting from 0, in which case the array will be encoded as a JSON object.)

# Arguments

Since PHP 5.3, the second argument to json_encode is a bitmask which can be one or more of the following.

As with any bitmask, they can be combined with the binary OR operator | .